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leetcode.com/problems/odd-even-linked-list/
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def oddEvenList(self, head: ListNode) -> ListNode:
if not head:
return None
root = head
root2 = head.next
odd = head
even = head.next
while even and even.next:
odd.next = odd.next.next
even.next = even.next.next
odd = odd.next
even = even.next
odd.next = root2
return root
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